Question

proof that : (x+y+z)^2 = (x+y+z)(x+y+z)

Answer 1

Answer:

Step-by-step explanation:

L.H.S. :

= (x+y+z)^2

= x^2 + y^2 + z^2 + 2(xy + yz + xz)

= x^2 + y^2 + z^2 + 2xy + 2yz + 2xz

R.H.S. :

= (x+y+z)(x+y+z)

= x^2 + xy + xz + xy + y^2 + yz + xz + yz + z^2

= x^2 + y^2 + z^2 + 2xy + 2yz+ 2xz ==> L.H.S.