Question

PROOF :-
The tangent at any point of a circle is perpendicular to the radius through the point of contact .

'' in detail , short answers not required ""

Answer 1

Referring to the figure:

OA=OC (Radii of circle)

Now OB=OC+BC

∴OB>OC (OC being radius and B any point on tangent)

⇒OA<OB

B is an arbitrary point on the tangent.

Thus, OA is shorter than any other line segment joining O to any

point on tangent.

Shortest distance of a point from a given line is the perpendicular distance from that line.

Hence, the tangent at any point of circle is perpendicular to the radius.

Answer 2

Answer:

Remove a healthy leaf from the potted plant.

Remove a part of the peel from the lower surface of the leaf. ...

Put a few drops of safranin stain in a watch glass.

After 2-3 minutes take out the peel and place it on a clean glass slide.