Question

proof time of decent is equal to time of acent ??

(class 11)

Answer 1

Please mark me as brainliest

Answer 2

Hey mate ^_^

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Solution:
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Initial speed of projected body = u

During ascent:

v = u + at
0 = u - gt
t = u/g

During descent:

v = u + at
v = 0 + gt’
t’ = v/g
t’ = u/g [v = u because body reaches the ground with speed equal to speed of projection]

∴ t = t’

Hence, for a body thrown upwards it’s time of ascent is equal to time of descent.

Hence proved,

Time of descent = Time of ascent

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