Question

proov Karna hai. Plz give me ANSWER

Answer 1

Hii ,, here is your solution

HOPE IT HELPS YOU!!!! :)

Answer 2

hello Frnd

here is your Answer.


Given that

$tan \: a \: \times tan \frac{a}{2} + 1 = sec \: a$
$\frac{ \sin(a) }{ \cos(a) } \times \frac{1 - \cos(a) }{ \sin(a) } + 1 \\ \frac{ \sin(a) - \cos(a) \sin(a) }{ \sin(a) \cos(a) } + 1 \\ \ \frac{ \sin(a) - \cos(a) \sin(a) }{ \sin(a) \cos(a) } + \ \frac {sin(a) cos(a)}{ \sin(a) \cos(a) } \\ \frac{ \cos(a) \sin(a) + \sin(a) - \sin(a) \cos(a) }{ \cos(a) \sin(a) } \\ \\ after \: elimination \: of \: 1st \: and \: 3rd \: \: \: \: \: \: \: \: we \: get \: \\ \\ \frac{ \sin(a) }{ \cos(a) \sin(a) } \\ \\ \frac{1}{ \cos(a) } \\ = \sec(a)$


hence proved




hope it helps
jerri