Math, asked by ullasgouthu, 9 months ago

proove 3+2
 \sqrt{5}
is irrartional​

Answers

Answered by Sudhir1188
10

Questions should be:

  • Prove that 3+2√5 is Irrational number.

ANSWER:

  • 3+2√5 is an Irrational number.

GIVEN:

  • Number = 3+2√5

TO PROVE:

  • 3+2√5 is an Irrational number.

SOLUTION:

Let 3+2√5 be a rational number which can be expressed in the form of p/q where p and q have no other common factor than 1.

=> 3+2√5 = p/q

=> 2√5 = (p/q) -3

=> 2√5 = (p-3q)/q

=> √5 = (p-3q)/2q

Here:

  • (p-3q)/2q is rational but √5 is Irrational.
  • Thus our contradiction is wrong.
  • 3+2√5 is an Irrational number.

NOTE:

  • This method of proving an irrational number is called contradiction method.
  • In this method we first contradict a fact then we prove that our supposition was wrong.
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