Math, asked by hemrajbhati120, 11 months ago

proove it with complete explanation​

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Answered by pastimeplays
1

Answer:

L.H.S \\\\=\sqrt{\frac{secA - 1}{secA + 1} } +\sqrt{\frac{secA + 1}{secA - 1} }\\\\=\sqrt{\frac{(secA - 1)(secA-1)}{(secA + 1)(secA-1)} }  + \sqrt{\frac{(secA + 1)(secA+1)}{(secA + 1)(secA-1)} }\\\\=\sqrt{\frac{(secA - 1)^{2}}{sec^{2}A - 1 }  }  + \sqrt{\frac{(secA + 1)^{2}}{sec^{2}A - 1 }  }\\\\=\sqrt{\frac{(secA - 1)^{2}}{tan^{2} A }  }  + \sqrt{\frac{(secA + 1)^{2}}{tan^{2} A }  }\\\\=\frac{secA - 1}{tanA}  +\frac{secA + 1}{tanA} \\\\= \frac{2secA}{tanA} \\\\= \frac{2}{cosA} \frac{cosA}{sinA} \\

=\frac{2}{sinA} \\\\=2cosecA\\\\=R.H.S

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