Question

proove sinA/1+cosA + 1+cosA/sinA = 2cosecA​

Answer 1

Step-by-step explanation:

{(sinA)^2+(1+cosA)^2}/(1+cosA)sinA

{(sinA)^2+1+(cosA)^2+2cosA}/(1+cosA)sinA

(1+1+2cosA)/(1+cosA)sinA

2(1+cosA)/(1+cosA)sinA

2/sinA

2cosecA