Math, asked by jappisingh2004, 6 months ago

proove sinA/1+cosA + 1+cosA/sinA = 2cosecA

Answers

Answered by tukaramshelar123

1

Step-by-step explanation:

{(sinA)^2+(1+cosA)^2}/(1+cosA)sinA

{(sinA)^2+1+(cosA)^2+2cosA}/(1+cosA)sinA

(1+1+2cosA)/(1+cosA)sinA

2(1+cosA)/(1+cosA)sinA

2/sinA

2cosecA

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