proove that 1-cosA/sinA
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Answered by
1
Answer:
hope it's helpful to you
Step-by-step explanation:
LHS [math]= \frac{1 - \cos A}{\sin A}[/math]
[math]= \frac{\sin A(1 - \cos A)}{\sin^2 A}[/math]
[math]= \frac{\sin A(1 - \cos A)}{1 - \cos^2 A}[/math]
[math]= \frac{\sin A(1-\cos A)}{(1 - \cos A)(1 + \cos A)}[/math]
[math] \frac{\sin A}{1 + \cos A}[/math]
[math]=[/math] RHS ■
Answered by
0
Answer:
LHS =1−cosAsinA
=sinA(1−cosA)sin2A
=sinA(1−cosA)1−cos2A
=sinA(1−cosA)(1−cosA)(1+cosA)
sinA1+cosA
= RHS ■
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