Question

proove that

1/cosec theta-cot theta - 1/sin theta = 1/sin theta - 1/cosec theta+cot theta ???

fast​

Answer 1

Solution

We have Given that

✨ 1/cosec theta + cot theta - 1/sin theta

        By proceeding.....

⭐1/cosec theta + cot theta × cosec theta - cot theta/cosec theta - cot theta - 1/sin theta

⭐cosec theta - cot theta/cosec² theta - cot² theta - 1/sin theta

⭐cosec theta - cot theta/1 - 1/sin theta

⭐sin theta(cosec theta - cot theta)-1/sin theta

➡1-cos theta - 1/sin theta

➡1/sin theta - cos theta/sin theta  - 1/sin theta

➡1/sin theta - cot theta - cosec theta 

➡1/sin theta - (cosec theta + cot theta)

➡1/sin theta - (cosec theta + cot theta)  × (cosec theta - cot theta)/cosec theta - cot theta)

➡ 1/sin theta - 1/(cosec theta - cot theta).

hnce proved

Answer 2

Answer:

Explanation:

1/cosec @ + cot @× cosec @ - cot @/cosec @ - cot @- 1/sin @

cosec @ - cot @/cosec^² @ - cot^² @ - 1/sin @

cosec @ - cot @/1 - 1/sin @

sin @(cosec @ - cot @)-1/sin @

1-cos @- 1/sin @

1/sin @ - cos @/sin @  - 1/sin @

1/sin @ - cot @ - cosec @

1/sin @ - (cosec @ + cot @)

1/sin @ - (cosec @+ cot @)  × (cosec @ - cot @)/cosec @ - cot @)

1/sin @ - 1/(cosec @ - cot @).

Hope it helps u