Question

proove that 1+secA/secA=sinsqureA/1-cosA

Answer 1

1+SecA/secA = 1/SecA+secA/secA
=CosA + 1
Now in SinsquareA/1-cosA
SinsquareA=1-CossquareA
so by factorising...and dividing we get
1+CossquareA=1+CossquareA on both sides

Answer 2

R.H.S
1-cos²A= {(1+cosA)(1-cosA)}/ 1-cosA
= 1 + cos A
L.H.S
1+sec A = 1 + 1/cosA=
( cosA+1 / cos A)/ (1 /cos A)
= 1 + cos A

L.H.S = R.H.S

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