Question

Proove that:- 1 + sin tita / 1 - sin tita = (sec tita + tan tita )²
Please answer as soon as possible ​

Answer 1

Step-by-step explanation:

Solving RHS

(sec theta + tan theta )²

= sec²theta + 2 × sec theta × tan theta + tan² theta

= 1/cos² theta + 2× (1/cos theta )× (sin theta / cos theta ) + sin² theta / cos² theta

= 1/cos²theta + 2sin theta / cos²theta + sin²theta / cos²theta

= (1+2sintheta + sin²theta )/cos²theta

=( 1 + sintheta )²/(1 - sin²theta )

By using algebraic formulae , we get ,

(1+sintheta ) ( 1+sintheta ) / (1 - sintheta )(1+ sintheta)

= (1+ sintheta )/ (1 - sin theta )