Question

Proove that √{(1+sinA)/(1-sinA)} = secA+tanA

Answer 1

Step-by-step explanation:

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Answer 2

√{( 1+ sin A)/(1-sin A)}= secA+tanA √{(1+ sinA/1-sinA)(1+sinA/1+sinA. =√1+sin^A/(1-sinA)(1+sinA) =√1+sin^A/cos^A

=1+sinA/cosA

=1/ cosA +sinA/cosA

=secA + TanA

hence proved

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