Question

proove that 2,3are the zeros of x^2-5x+6​

Answer 1

Step-by-step explanation:

x^2-5x+6

x^2-3x-2x+6

x(x-3)-2(x-3)

(x-3)(x-2)=0

hence proved x=2,3

hope it help u buddyyy☺☺☺☺☺

Answer 2

Step-by-step explanation:

u can do also by this method

putting x=2 in the eq we get

(2)^2-5(2)+6

=4-10+6

10-10=0

h/p

similarly u can put x=3 and can prove it