proove that 2sinxsin3x-1=0
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I think this must not be a proof question rather it should be a question to find the value of x given the equation. why I think it must not be a proof question is simply put x = 0° and LHS will be -1 which is not equal to RHS. So, it is not correct for every value of x and hence not a proof question.
I am proceeding to solve it, given
2sinxsin3x - 1 = 0
cos(3x-x) - cos(3x+x) - 1 = 0
cos2x - cos4x - 1 = 0
cos2x - (2cos^2(2x) - 1) - 1 = 0
cos2x - 2cos^2(2x) = 0
cos2x(1 - 2cos2x) = 0
case 1
cos2x = 0 = cos π/2
2x = 2nπ +_ π/2
x= nπ +_ π/4
case 2
1-2cos2x = 0
cos2x = 1/2 = cosπ/6
2x = 2nπ +_ π/6
x= nπ +_ π/12
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