proove that 3a3-4a2+3=a+1 if you do so i will mark you brainlist
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a+b+c)3=[(a+b)+c]3=(a+b)3+3(a+b)2c+3(a+b)c2+c3
a+b+c)3=[(a+b)+c]3=(a+b)3+3(a+b)2c+3(a+b)c2+c3=>(a+b+c)3=(a3+3a2b+3ab2+b3)+3(a2+2ab+b2)c+3(a+b)c2+c3
a+b+c)3=[(a+b)+c]3=(a+b)3+3(a+b)2c+3(a+b)c2+c3=>(a+b+c)3=(a3+3a2b+3ab2+b3)+3(a2+2ab+b2)c+3(a+b)c2+c3=>(a+b+c)3=a3+b3+c3+3a2b+3a2c+3ab2+3b2c+3ac2+3bc2+6abc
a+b+c)3=[(a+b)+c]3=(a+b)3+3(a+b)2c+3(a+b)c2+c3=>(a+b+c)3=(a3+3a2b+3ab2+b3)+3(a2+2ab+b2)c+3(a+b)c2+c3=>(a+b+c)3=a3+b3+c3+3a2b+3a2c+3ab2+3b2c+3ac2+3bc2+6abc=>(a+b+c)3=a3+b3+
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here is your answer mate mark as brainliest
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please mark me as brainliest
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