proove that
(cos - sin)²+(cos + sin)² = 2
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Correct Question:
Prove that (cosA - sinA)² + (cosA + sinA)² = 2
SOLUTION:
(cosA - sinA)² + (cosA + sinA)² = 2
We know that,
(a - b)² = a² + b² - 2ab
(a + b)² = a² + b² + 2ab
= cos²A + sin²A - 2cosA. sinA + cos²A + sin²A + 2cosA. sinA
= cos²A + sin²A + cos²A + sin²A
= 2(cos²A + sin²A)
We know that,
cos²A + sin²A = 1
= 2 (1)
= 2,,
LHS = RHS
Hence, proved!
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