Proove that: cosec A - cot A= √1-cos A/ 1+cos A
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Answer :,
1) as cosec a=1/sin a
and cot a=cos a / sin a
so , L.H.S. = cosec a - cot a = 1 /sin a - cos a/ sin a
= (1-cos a) / sin a =(1- cos a)(1 + cos a) / sin a * (1 + cos a )
=1 - cos^2 (a) / sin a *(1+ cos a) =
sin ^2(a)/sin a * (1 + cos a)= sin a /(1 + cos a)= R.H.S.
this is standard method to solve such problem , otherwise you can solve as
2. as taking
sin a =p/h
cos a =b/h
cosec a= h/ p
cot =b /p
where p,b,h are sides of a right angled triangle ,
p=perpendicular side
b=base of the triangle
h= hypotenuse
put these valve in L.H.S. and R.H.S. and hence prove L.H.S. = R.H.S. .
hope it will help
DENIKA:
Didn't get the final answer though. It's supposed to be √1- cos A/ 1+ cos A
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