proove that cosecA/cosecA-1 +cosecA /cosecA+1 =2+2tan squareA =2sec squareA
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Answered by
2
Hi ,
Cosec A/(cosec A-1) + cosecA/(cosec A + 1 )
= Cosec A [1/(cosec A-1)+1/(cosec A+1)]
= Cosec A [( cosec A+1+cosecA-1)/(cosecA-1)(cosec A+1) ]
= 2cosec²A / [ cosec² A - 1 ]
= 2cosec²A / cot² A
= 2 ( 1/sin² A ) / ( cos² A / sin² A )
= 2/ cos² A
= 2sec²A ----( 1 )
= 2 ( 1 + tan ² A )
= 2 + 2 tan² A ----- ( 2 )
I hope this helps you.
: )
Cosec A/(cosec A-1) + cosecA/(cosec A + 1 )
= Cosec A [1/(cosec A-1)+1/(cosec A+1)]
= Cosec A [( cosec A+1+cosecA-1)/(cosecA-1)(cosec A+1) ]
= 2cosec²A / [ cosec² A - 1 ]
= 2cosec²A / cot² A
= 2 ( 1/sin² A ) / ( cos² A / sin² A )
= 2/ cos² A
= 2sec²A ----( 1 )
= 2 ( 1 + tan ² A )
= 2 + 2 tan² A ----- ( 2 )
I hope this helps you.
: )
Answered by
6
Hi,
Please see the attached file!
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Please see the attached file!
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