Question

proove that cotA+cosecA-1÷cotA-cosecA+1=1+cosA÷sinA

Answer 1

cosec A + cot A - 1 / cot A - cosec A + 1 
we know that,cosec ² A - cot ² A = 1 
substituting this in the numerator 
cosec A + cot A -(cosec ² A - cot ² A) / (cot A - cosec A + 1) 
x²-y²= (x+y)(x-y) 
cosec A + cot A - (cosec A + cot A) (cosec A - cot A) / (cot A - cosec A + 1) 
taking common 
(cosec A + cot A)(1-cosec A + cot A) / (cot A - cosec A + 1) 
cancelling like terms in numerator and denominator 
we are left with cosec A + cot A 
= 1/sin A + cos A/sin A 
= (1+cos A) / sin A
GIVE A THUMBS UP  :-) 

Answer 2

Answer:-

Here it is :-