proove that sum of all the angle of a quadrilateral is 360
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Heya!!
ln a Quadrilateral ABCD ,
By drawing a diognal by joining two opposite vertices , (for eg - A and C)
We obtain two triangles - Triangle ACD and Triangle ABC
We know that sum of all angles of a triangle = 180°
Triangle ABC + Triangle ACD = ABCD
Sum of all angles of ABC + Sum of all angles of ACD = Sum of angles of quadrilateal ABCD
180 + 180 = 360° = sum of all angles of a quadrilateral
(proved)
====================================
ln a Quadrilateral ABCD ,
By drawing a diognal by joining two opposite vertices , (for eg - A and C)
We obtain two triangles - Triangle ACD and Triangle ABC
We know that sum of all angles of a triangle = 180°
Triangle ABC + Triangle ACD = ABCD
Sum of all angles of ABC + Sum of all angles of ACD = Sum of angles of quadrilateal ABCD
180 + 180 = 360° = sum of all angles of a quadrilateral
(proved)
====================================
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