Question

proove that x^logy-logz y^logz-logx z^logx-logy = 1

Answer 1

=LHS
= x^(log y/z).y^(log z/x).z^(logx/y) 
= Antilog * log [x^(log y/z).y^(log z/x).z^(logx/y)] 
= Antilog * [logx (logy - logz + logy (logz - logx) + logz (logx - logy)] 
= Antilog 0 
= 1 
= RHS.