Proove that x square x is divisible by 2 for all positive integer
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Here's your answer..
Step-by-step explanation:
[tex]x^{2}-x\\=x(x-1)[\tex]
if x is a positive integer then the given expression turns out to be an even integer times an odd integer or an odd integer times an even integer for x being odd or even
As we know that every even integer is divisible by 2
Therefore[tex]x^{2}-x[\tex] is divisible by 2.
Hope it helps.
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