Math, asked by paraswaningmailcom, 1 year ago

proove this gimme full solution please

Attachments:

Answers

Answered by Swaroop1234
1
 LHS={ \tan(A) }^{2} { \cos(A) }^{2} \\ = \frac{ { \sin(A) }^{2} }{ { \cos(A) }^{2} } \times { \cos(A ) }^{2} \\ = { \sin(A ) }^{2} \\ = 1 - { \cos(A ) }^{2}= RHS
Therefore, LHS=RHS(proved)
Similar questions