proove this plz URGENT!!! i will mark u brainliest...
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Answer:
L.H.S.
sec(1-sinA)(secA+tanA)
=1/cosA[1-sinA][(1/cosA)+(sinA/cosA)]
=[(1-sinA)/cosA][(1+sinA)/cosA]
=[(1-sinA)(1+sinA]/cos^2A
=(1-sin^2A)/cos^2A{Reason:(a+b)(a-b)=a^2-b^2}
=cos^2A/cos^2A{Reason:1-sin^2A=cos^2A}
=1
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hope this answer help you
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the second pic is the left side of answer
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