Question

Propan-1-ol may be prepared by the reaction of propene with
(a) H₃BO₃ (b) H₂SO₄/H₂O
(c) B₂H₆ ,NaOH–H₂O₂
O
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(d) CH₃ – C-OH

Answer 1

Explanation:

I think the correct answer is (c)

Answer 2

Propan-1-ol may be prepared by the reaction of propene with

(c) B₂H₆ ,NaOH–H₂O₂

The conversion of propene to propanol is an example of Anti-Markonikoff addition.

The conversion is done in the presence of diborane (B₂H₆) and in the presence of hydrogen peroxide (H₂O₂) or peroxide ions and then hydrolysis in the presence of aqueous OH⁻ (like KOH, NaOH) solutions to get the required propan-1-ol.

So, option (c) is correct.

If the reaction was done in the presence H₂O and aqeous KOH, Markonikoff's rule of addition is followed and we get propan-2ol as the product.