Question

Propane (C3H8) reacts with Oxygen gas to form Carbon Dioxide and Water. If 2.8 moles of Propane reacts with excess Oxygen how many grams of CO2 will it form? (3)

Answer 1

Answer:

C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)

Approx. 22⋅g carbon dioxide will result.

Explanation:

the equation above, 3 moles of carbon dioxide result from every mole of propane combusted.

Answer 2

2.8 moles of propane will produce 205.34 grams of CO2.

The balanced chemical equation for the reaction of propane (C3H8) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is:

C3H8 + 5O2 → 3CO2 + 4H2O

From the balanced equation, we can see that 1 mole of propane reacts with 5 moles of oxygen to form 3 moles of carbon dioxide. Therefore, we can use the mole ratio to calculate the amount of CO2 produced from 2.8 moles of propane.

Mole ratio of propane to carbon dioxide = 1 : 3/5 = 5/5 : 3/5 = 3 : 5

So, for every 3 moles of propane reacted, 5 moles of CO2 are produced. Therefore, for 2.8 moles of propane reacted, the amount of CO2 produced is:

2.8 moles propane × (5 moles CO2 / 3 moles propane) = 4.67 moles CO2

Finally, we can use the molar mass of carbon dioxide (44.01 g/mol) to convert moles of CO2 to grams:

4.67 moles CO2 × 44.01 g/mol = 205.34 g CO2

Therefore, 2.8 moles of propane will produce 205.34 grams of CO2.

For such more questions on reactions,

https://brainly.in/question/6735262

#SPJ6