Question

Propane. C3H8 undergoes complete combustion to produce carbon dioxide and water vapor, what mass of carbon dioxide is produced during the combustion of 17.6g of propane

Answer 1

Answer:

The common currency of chemistry is moles. So it is necessary to change the mass of propane to moles. Then write a balance equation so the moles of propane to moles of Carbon Dioxide. Finally moles of Carbon Dioxide must be changed to grams.

C

3

H

8

+

5

O

2

=

=

3

C

O

2

+

4

H

2

O

This is the balance equation for the burning of propane in Oxygen.

From the equation it can be seen that 1 mole of propane makes 3 moles of Carbon Dioxide a ratio of 1:3

Convert 22 grams of propane to moles by dividing by the molar mass of propane.

3 x 12 = 36 grams

1 x 8 = + 8 grams

total = 44 grams/ mole.

22

44

= .5 moles of propane.

Using the ratio of 1:3 .5 = 3( .5) = 1.5 moles of Carbon Dioxide.

Now multiply 1.5 moles of Carbon Dioxide by the molar mass of Carbon Dioxide

1 x 12 = 12 grams

2 x 16 = +32 grams

total = 44 grams /mole.

1.5 moles x 44 grams/mole = 66 grams.

Explanation:

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