Question

Proper Answer will mark as brainliest .





Diameter of a circle is 26cm and length of the chord of the circle is 24cm .Find the distant of the chord from the centre

Answer 1

d=26c.m.

r=13c.m. if we draw a hieght to the cord from the center than the cord divided into two parts which are equal

let AB is the chord

and the height touches the chord at point X

than AX = BX

AX=24/2=12cm

OA is the radius which is equal to 13cm

in triangle OAX,measure of OXA =90degree

and OA is the hypotenus(h)

AX and OX are touching the right angle v so the are p and b

as to Pythagorean theorem,h^2=p^2+ b^2

OA^2=Ax^2+OX^2

13^2=12^2+OX^2

169= 144+ OX ^2

169-144=OX ^2

25=0X^2

OX =√25

hope it helps

Answer 2

your answer will be the following attachment.