Math, asked by Nivejoshi107200, 1 year ago

proper differentiation with steps for root sin x...no irrelevant answers ..

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Answered by astitvastitva

$\frac{d}{dx} \sqrt{sinx}$
= $\frac{1}{2 \sqrt{sinx} } .cosx$ (First, differentiation of root function and then,multiply by differentiation of sine function)
= $\frac{cosx}{2 \sqrt{sinx} }$

astitvastitva: That's the chain rule. First multiply the outermost function (in this case it is the root function) then we have to differentiate the inner function (that is sine function) and multiply it with the rest.

astitvastitva: If there were another function inside sine, for example x, then we would have to differentiate it and multiply with the result. As derivative of x is 1, there would be no casual effect on the answer.

astitvastitva: You're welcome.

Answered by Anonymous

this is your answer......

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