Math, asked by lvemahi, 2 months ago

Proper solution :-
A box of weight 100 N is lifted to a height of 10 m above ground. How much potential energy will be stored in the box?​

Answers

Answered by Anonymous
3

\begin{gathered}\underline{\underline{\sf{ \color{purple}{\qquad Solution\:: \qquad} }}}\\\\\end{gathered}

Given that,

• Weight = 100 N

• Height = 10 m

\begin{gathered}\dag\;{\underline{\frak{As\;we\;know\;that,}}}\\ \\\end{gathered}

\begin{gathered}\star\;{\boxed{\sf{\purple{Weight= Mass \times Acceleration }}}}\\ \\\end{gathered}

\begin{gathered}\qquad \quad {:} \implies \sf \: {100 = Mass \times 10 } \\\end{gathered}

\begin{gathered}\qquad \quad {:} \implies \sf \: { \dfrac{100}{10} = Mass } \\\end{gathered}

\begin{gathered}\qquad \quad {:} \implies \sf \: { Mass = \cancel\dfrac{100}{10} } \\\end{gathered}

\begin{gathered}\qquad \quad {:} \implies \sf{ Mass = 10 \: kg } \\\\\\\end{gathered}

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\begin{gathered}\dag\;{\underline{\frak{Again}}}\\ \\\end{gathered}

\begin{gathered}\star\;{\boxed{\sf{\purple{Potential ~ energy= Mass \times Acceleration \times Hight }}}}\\ \\\end{gathered}

\begin{gathered}\qquad \quad {:} \implies \sf \: {Potential \: energy = 10 \times 10 \times 10 } \\\end{gathered}

\begin{gathered}\qquad \quad {:} \implies \sf{ Potential \: energy = 1000 \: J } \\\\\\\end{gathered}

\begin{gathered}\sf \: ∴ \: Hence, \: the \: potential \: energy \: is \: 1000 J \\\\\end{gathered}

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Answered by MissLuxuRiant
1

\large{\underline{\underline{\sf{ \maltese \: {Given:-}}}}}

Weight = 100 N

Height = 10 m

\large{\underline{\underline{\sf{ \maltese \: {To \: find:-}}}}}

Potential energy = ?

\large{\underline{\underline{\sf{ \maltese \: {Solution:-}}}}}

➊ We know that:–

\qquad \bull \bf \: {Weight = Mass \times Acceleration }

\begin{gathered}\begin{gathered}\begin{gathered}\qquad \quad {:} \longrightarrow\sf \: {100 = mass \times 10 } \\\end{gathered}\end{gathered} \end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered}\qquad \quad {:} \longrightarrow\sf \: { \dfrac{100}{10} = mass } \\\end{gathered}\end{gathered} \end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered}\qquad \quad {:} \longrightarrow\sf \: { mass = \cancel\dfrac{100}{10} } \\\end{gathered}\end{gathered} \end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered}\qquad \quad {:} \longrightarrow\sf \: \underline{ \boxed {\sf{mass = 10 \: kg }}} \\\end{gathered}\end{gathered} \end{gathered}

➋ We know that:–

\qquad \bull \bf \: { Potential \: energy=mass \times acceleration \times height}

\begin{gathered}\begin{gathered}\begin{gathered}\qquad \quad {:} \longrightarrow\sf \: {potential \: energy = 10 \times 10 \times 10 } \\\end{gathered}\end{gathered} \end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered}\qquad \quad {:} \longrightarrow \underline{ \boxed{\sf \: {potential \: energy = 1000 \: J}}} \\\end{gathered}\end{gathered} \end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered}\large \quad \therefore\sf \: { The \: correct \: option \: is \: \underline{\underline{1000 \: J}}} \\\end{gathered}\end{gathered} \end{gathered}

The potential energy is 1000 J.

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