Math, asked by Anonymous, 10 months ago

properties of logarithm​

Answers

Answered by ShivajiMaharaj45
3

Step-by-step explanation:

\sf log_{x}{1} = 0

\\

\sf log_{x}{ab} = log_{x}{a} + log_{x}{b}

\\

\sf log_{x}{\frac {a}{b}} = log_{x}{a} - log_{x}{b}

\\

\sf log_{x}{{a}^{b}} = blog_{x}{a}

\\

\sf log_{{a}^{b}}{x} = \frac{1}{b} log_{a}{x}

\\

\sf {x}^{log_{x}{y}} = y

\\

THANKS!!!

Answered by Anonymous
2

Step-by-step explanation:

handwriting problem is there please understand

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