Properties of Triangles given figure, P is a point on the side BC of AABC. Prove AB + BC + AC) > 2 AP. en ABP. AB+ BP > AP En AAPC, PC + AC > AP. Now, add the corresponding sides. CD is a quadrilateral. ve that (AB + BC + CD + DA) > (AC + BD) B P O is point in a exterior of AABC, show that LOA +OB +OC) > (AB + BC + CA). Rint. Join OA, OB, OC. From AAOB, OA+OB > AB. From ABOC, OB+OC > BC. From AAOC, OA +OC > CA. OREM
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Step-by-step explanation:
In△ABP,AB+BP>AP
In△APC,PC+AC>AP
Now, add the corresponding sides.
(AB+BC+AC)>2AP
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