Question

Propionic acid with Br₂/P yields a dibromo product. Its
structure would be:
Br
|
(a) H– C – CH₂COOH
|
Br
(b) CH₂Br – CH₂ – COBr
Br
|
(c) CH₃ – C – COOH
|
Br
(d) CH₂ Br – CHBr – COOH

Answer 1

Answer:

Propionic acid with Br₂/P yields a dibromo product. Its

structure would be:

Br

|

(a) H– C – CH₂COOH

|

Br

(b) CH₂Br – CH₂ – COBr

Br

|

(c) CH₃ – C – COOH

|

Br

(d) CH₂ Br – CHBr – COOH

Answer 2

Its structure would be:

Reaction : CH₃–CH₂–COOH + Br₂/P => X

• The above reaction is known as Hell–Volhard–Zelinsky halogenation.

• In which, alpha hydrogen atom of respective acid gets replaced by bromine atom.

• Hence when we carry out this reaction, we'll get two bromine atom at alpha carbon atom.

Structure of X would be :

Br

|

CH₃ – C – COOH

|

Br

Correct option : (c)