Question

Proposed communication satellite revolve round the earth in circular orbit at a height 35880 km above the earth surface .find the period of revolution of the satellite in hours​

Answer 1

Explanation:

Time period of the satellite is given by: T=2π

g

r

Almost close to surface of Earth ⟹r=R

e

∴ Time period, T=2π

9.8

6400×10

3

Time period, T=5077 seconds