Question

- Prore :-
tan β +cotβ : secβ cosecβ​

Answer 1

Answer:

Answer in attachment.. Solved using simple trigonometric formulas. Hope it helps

Answer 2

Step-by-step explanation:

$l.h.s = \tan( \beta ) + \cot( \beta ) \\ = \frac{ \sin( \beta ) }{ \cos( \beta ) } + \frac{ \cos( \beta ) }{ \sin( \beta ) } \\ = \frac{ \sin( \beta ) \times \sin( \beta ) + \cos( \beta ) \times \cos( \beta ) }{ \cos( \beta ) \times \sin( \beta ) } \\ = ({ \sin }^{2} \beta + { \cos}^{2} \beta) \times \frac{1}{ \sin( \beta ) \cos( \beta ) } \\ = 1 \: \: \times cosec \beta \: \times \sec( \beta ) \\ = cose \beta . \sec( \beta ) \: \: proved$