Question

Proton has a mass of 1.67 x 10^-27 kg proton has an initial speed of

Answer 1

Answer: (a)  We know V2=V02+2aΔx. Thus, 

 

v=V02+2aΔx=(2.4×107 m/s)2+2(3.6×1015 m/s2)(0.035 m)=2.9×107 m/s.

(b) The initial kinetic energy is 

Ki=21 mv02=21(1.67×10−27 kg)(2.4×107 m/s)2=4.8×10−13 J.

The change in kinetic energy is Δ K=6.9×10−13 J−4.8×10−13 J=2.1×10−13 J

Have a good day thank you ❤️