Proton has a mass of 1840 times that of an electron if a proton is accelerated from rest by a pd of 1 v its kinetic energy is
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When in motion then we have to make the following assumptions :
the potential energy remains 0
In-order to calculate the kinetic Energy:
PE* = 0,
KE* = 1/(2mv^2)
Now since PE +KE = Total energy =PE* + KE*
qV + 0 = 0 + 1/2mv^2
The second formulae we can use to calculate the kinetic Energy is given by
KE = qV
where the charge of the proton is 1.6 x 10^-15 C and where v is the potential difference.
Kinetic Energy is given by
1.6 x 10^-19C x 1v= 1.6 x10^-19 J
Therefore, the answer is given by 1.6 x 10^-19J
the potential energy remains 0
In-order to calculate the kinetic Energy:
PE* = 0,
KE* = 1/(2mv^2)
Now since PE +KE = Total energy =PE* + KE*
qV + 0 = 0 + 1/2mv^2
The second formulae we can use to calculate the kinetic Energy is given by
KE = qV
where the charge of the proton is 1.6 x 10^-15 C and where v is the potential difference.
Kinetic Energy is given by
1.6 x 10^-19C x 1v= 1.6 x10^-19 J
Therefore, the answer is given by 1.6 x 10^-19J
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