Proton with kinetic energy 8eV IS MOVING IN A UNIFORM B , the kinetic energy of a deutron moving in same path in same B in eV is
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Answer:
4e = v
Explanation:
4eV
Kinetic Energy of a charged particle in a magnetic field is KE=
2m
P
2
=
2m
(qBr)
2
=
2m
q
2
B
2
r
2
∴
K
p
K
α
=(
q
p
q
α
)
2
m
α
m
p
=1×
2
1
=
2
1
∴K
α
=K
p
×
2
1
=8×
2
1
=4eV
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