Question

protractor.
11. The perimeter of a rhombus is equal to the circumference of a circle. If each side of the
rhombus measures 11 cm, then find the radius of the circle.
2. A piece of thin wire in the form of an equilateral triangle of side 88 dm in hont int​

Answer 1

Step-by-step explanation:

Find Perimeter of Rhombus

Perimeter of Rhombus = 4 * Side

We have given side = 11 cm

Perimeter of Rhombus = 11 * 4

=> 44 cm

Find Radius of the Circle

According to the Question

Perimeter of Rhombus is equal to the circumference of a Circle

=> 2 * 22/7 * r = 44 cm

=> r = 44/2 *  7/22

=> r = 7 cm

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Answer 2

$<font color="purple">$1)★FIND:

the radius of the circle=? .

★GIVEN,

The perimeter of a rhombus is equal to the circumference of a circle.

➡️each side of the

rhombus =11 cm

★SOLUTION:

Perimeter of a rhombus = 4s

Perimeter of a rhombus = 4 ×11

➡️44cm

Now,

according to the given question.

Perimeter of the rhombus = Circumference of the circle

➡️ 2πr = 44 cm

➡️ 2(22/7)r = 44

➡️44r = 44×7

➡️r = 7

➡️r =7 cm

So, the radius of the circle is 7 cm.

$<font color="green">$2)★FIND:

Diameter of the wire =?

★GIVEN:

A piece of thin wire in the form of an equilateral triangle of side = 88 dm

(1 dm=10cm)

★SOLUTION:

Perimeter of triangle=perimeter of circle.

Perimeter of triangle =A+B+C

Perimeter of triangle =88dm+88dm+88dm

➡️264dm=2640cm

Perimeter of triangle = perimeter of circle.

Perimeter of circle =2πr=2640cm

2πr = 2640

2r = 2640/π

2r = 2640 × 7/22

2r = 840 cm = 84 dm

Hence, the diameter of the wire is 84dm .