Question

protractor.
11. The perimeter of a rhombus is equal to the circumference of a circle. If each side of the
rhombus measures 11 cm, then find the radius of the circle.
2. A piece of thin wire in the form of an equilateral triangle of side 88 dm in hont int​

Answer 1

Step-by-step explanation:

perimeter of rhombus= 4 × side

=11×4

=44cm

circumference of circle=2×pie×r

44=2×22/7×r

r=44/2×7/22

r=7cm

Answer 2

Answer:

$\huge\underline\bold\blue{solution}$

$\huge\ given : -$

The perimeter of a rhombus is equal to the circumference of a circle.

Each side of rhombus measures 11 cm.

$\huge\ find : -$

Radius of the circle ??

$\huge\ answer : -$

Perimeter of rhombus = 4 x Side

= 4 x 11

= 44 cm

$\huge\ atq : -$

Perimeter of rhombus= circumference of circle

Circumference of circle= 2πr

So, 44 = 2πr

44 = 2 x 22/7 x r

r = 44/2 x 7/22

r = 7

$\large\blue{the \: radius \: of \: the \: circle \: is \: 7cm}$