Prove (0.6)^0 -(0.1)^-1 ÷(3/8)^-1×(3/2)³+(-1/3)^-1=1
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(a-b)=6 the square it
(a-b)^2=36
a^2-2ab-b^2=36
a^2+b^2=76
a^3-b^3=(a-b)(a^2+ab+b^2)
=(6)(76+20)
=(6)(96)
=576=Ans.
(a-b)^2=36
a^2-2ab-b^2=36
a^2+b^2=76
a^3-b^3=(a-b)(a^2+ab+b^2)
=(6)(76+20)
=(6)(96)
=576=Ans.
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