prove 1=0.999 explain breifly
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hlw mate,
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ur answer,
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number "0.9999..." can be "expanded" as:
0.9999... = 0.9 + 0.09 + 0.009 + 0.0009 + ...
In other words, each term in this endless summation will have a "9" preceded by some number of zeroes. This may also be written as:
That is, this is an infinite geometric series with first term a = 9/10 and common ratio r = 1/10. Since the size of the common ratio r is less than 1, we can use the infinite-sum formula to find the value:
So the formula proves that 0.9999... = 1
______________
ur answer,
=============
⬇️⬇️⬇️⬇️⬇️⬇️
number "0.9999..." can be "expanded" as:
0.9999... = 0.9 + 0.09 + 0.009 + 0.0009 + ...
In other words, each term in this endless summation will have a "9" preceded by some number of zeroes. This may also be written as:
That is, this is an infinite geometric series with first term a = 9/10 and common ratio r = 1/10. Since the size of the common ratio r is less than 1, we can use the infinite-sum formula to find the value:
So the formula proves that 0.9999... = 1
bhawink:
wrong
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