prove 1+1=3 if anyone can i wil mark them as brainlist. I think no one
Answers
Answered by
1
1st method :
1 = 1
41 - 40 = 61 - 60
16 + 25 – 40 = 36 + 25 – 60
4² + 5² – 2 * 4 * 5 = 6² + 5² – 2 * 6 * 5
(4 – 5)² = (6 – 5)²
4 – 5 = 6 – 5
4 = 6
2 = 3
1 + 1 = 3
2nd method:
Let
a=b
Multiply both sides by b,
ab=b^2
Subtract a^2 from both sides and factorize:
ab-a^2=b^2-a^2
a(b-a)=(b+a)(b-a)
Simplify and add 1 to both sides:
a=b+a
a+1=b+a+1
Now since a=b (the starting point of this proof), we can write this as:
a+1=a+a+1
a+1=2a+1
And in the case where a=1, we have:
1+1=2+1
So, therefore,
1+1=3
1 = 1
41 - 40 = 61 - 60
16 + 25 – 40 = 36 + 25 – 60
4² + 5² – 2 * 4 * 5 = 6² + 5² – 2 * 6 * 5
(4 – 5)² = (6 – 5)²
4 – 5 = 6 – 5
4 = 6
2 = 3
1 + 1 = 3
2nd method:
Let
a=b
Multiply both sides by b,
ab=b^2
Subtract a^2 from both sides and factorize:
ab-a^2=b^2-a^2
a(b-a)=(b+a)(b-a)
Simplify and add 1 to both sides:
a=b+a
a+1=b+a+1
Now since a=b (the starting point of this proof), we can write this as:
a+1=a+a+1
a+1=2a+1
And in the case where a=1, we have:
1+1=2+1
So, therefore,
1+1=3
Answered by
0
Here's your answer...
Let's see...
Let an equation be a root 2 = a
Squaring on both sides...
2a² = a²
Cutting a from both sides...
2 = 1
Now, since we have established that 1 = 2,
1+1 = 1+2 = 3
Let's see...
Let an equation be a root 2 = a
Squaring on both sides...
2a² = a²
Cutting a from both sides...
2 = 1
Now, since we have established that 1 = 2,
1+1 = 1+2 = 3
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