prove 1+2+3+4+5+6+7+8+9........=-1/12
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Answered by
0
Answer:
-1/2 this
answer
Step-by-step explanation:
-3c=1-2+3-4+...=1/(1+1)2
=-1/12
Answered by
0
Let A = 1-1+1-1....... -> eq.1
1-A = 1-(1-1+1-1.......)
1-A = 1-1-1+1-1.......
1-A = A [from eq.1]
1 = 2A
A = 1/2 -------> eq.2
Let B = 1-2+3-4+5...... -> eq.3
A-B = (1-1+1-1+1.....) - (1-2+3-4....)
A-B = 1-1+1-1...... -1+2-3+4......
Rearranging,
A-B = (1-1) + (-1+2) + (1-3) + (-1+4).....
A-B = 1-2+3-4.....
A-B = B [from eq.3]
A = 2B
1/2 = 2B [from eq.2]
B = 1/4 --------> eq.4
Let C = 1+2+3+4+5+....... ->eq.5
B-C = (1-2+3-4+5.....) - (1+2+3+4+.....)
B-C = 1-2+3-4.... -1-2-3-4.....
B-C = (1-1) + (-2-2) + (3-3) + (-4-4)......
B-C = -4 -8 -12.....
B-C = -4(1+2+3+4+.....)
B-C = -4C [from eq.5]
B = -3C
1/4 = -3C [from eq.4]
C = -1/12
1+2+3+4+5+....... = -1/12
Proved
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