PROVE - 1 = 2
(a+b)²
a² +b² + 2ab
Answers
Answer:
Step 1: Draw a square ACDF with AC=a units.
Step 2: Cut AB=b units so that BC=(a−b) unts.
Step 3: Complete the squares and rectangle as shown in the diagram.
Step 4: Area of yellow square IDEO= Area of square ACDF− Area of rectangle GOFE− Area of rectangle BCIO− Area of red square ABOG
Therefore, (a−b)
2
=a
2
−b(a−b)−b(a−b)−b
2
= a
2
−ab+b
2
−ab+b
2
−b
2
= a
2
−2ab+b
2
Hence, geometrically we proved the identity (a−b)
2
=a
2
−2ab+b
2
.
Question ⤵️
PROVE - 1 = 2
(a+b)²
a² +b² + 2ab
Answer ⤵️
Step 1: Draw a square ACDF with AC=a units.
Step 2: Cut AB=b units so that BC=(a−b) unts.
Step 3: Complete the squares and rectangle as shown in the diagram.
Step 4: Area of yellow square IDEO= Area of square ACDF− Area of rectangle GOFE− Area of rectangle BCIO− Area of red square ABOG
Therefore,
(a−b)² = a² − b(a − b) − b(a −b ) − b²
= a² − ab+b²− ab+b²− b²
= a² −2ab + b²
Hence, geometrically we proved the identity
(a−b)²= a²−2ab + b²
Hope it helps you ✌️
Step-by-step explanation:
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