prove √(1- sin A / 1 + sin A) = sec a - tan a
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Step-by-step explanation:
=√1-sinA/1+sinA
=√(1-sinA)(1-sinA)/(1+sinA)(1-sinA)
=√(1-sinA)^2/(1-sin^2A)
=1-sinA/cosA
=1/cosA-sinA/cosA
=secA-tanA
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