prove:
(1 - sinA)(1 + sinA)(1 + tan Square A) = 1
Answers
Answered by
1
Answer:
(1-sinA)(1+sinA)=1²-sin²A=1-sin²A=cos²A
and 1+tan²A=sec²A
So, (1-sinA)(1+sinA)(1+tan²A)=cos²A.sec²A
=(cos²A).(1/cos²A). ( cosA.secA=1)
=1
Answered by
7
To prove :-
Solution :-
» Consider LHS
» Apply formula (1-sinA) (1+sinA) = 1-sin²A
» Apply formula (1-sin²A) = cos²A
» Apply formula (1+tan²A) = sec²A
» Apply formula cos²A = 1/sec²A
» LHS = RHS
Hence proved
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