Math, asked by vanshitab1109, 9 months ago

Prove : (1-sinA) /(1+sinA) = 1+tanA^2 - 2tanAsecA

Answers

Answered by sandy1816

1

Step-by-step explanation:

1-sinA/1+sinA

=(1-sinA)²/1-sin²A

=(1+sin²A-2sinA)/cos²A

=sec²A+tan²A-2tanAsecA

=1+tan²A+tan²A-2tanAsecA

=1+2tan²A-2tanAsecA

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