Prove : (1-sinA) /(1+sinA) = 1+tanA^2 - 2tanAsecA
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Step-by-step explanation:
1-sinA/1+sinA
=(1-sinA)²/1-sin²A
=(1+sin²A-2sinA)/cos²A
=sec²A+tan²A-2tanAsecA
=1+tan²A+tan²A-2tanAsecA
=1+2tan²A-2tanAsecA
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