Question

prove √1+sinA÷1-sinA=tan A+sec A

Answer 1

-sin A)2 / (1-sin2 A ) = √(1-sin A)2 / cos2 A = (1-sin A) / cos A = (1/cos A - sin A/cos A) = sec A - tan A. √1-sin A / 1+sin A = sec A ...

Answer 2

Here is your answer..