prove
1. sinA+2cosA/sin2A+2sinA*cosA=cosecA
2. (tan2A/sec2A) / (sin2A/cosec2A)=cosec2A
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Answer:
please ask properly okkkkk
Answered by
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Step-by-step explanation:
sinA+2cosA÷sin2A+2sinA.cosA=cosecA
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